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Fluid force on vertical side of tank the weight density of water is 62.4
Fluid force on vertical side of tank the weight density of water is 62.4











fluid force on vertical side of tank the weight density of water is 62.4

Finally, simplifying, showing x as a function of y: In this case, because $x^2+y^2=z^2$ and $z^2$ can be equal to the radius, that gives $x^2+y^2=2$. Radius of each discĪttempting to follow this video, I was able to see that I could write the radius of each disc as a function of y by using the Pythagorean theorem. The Volume of a disc is $\pi r^2h$ so while the height of each disc will end up being equivalent to dy, I will have to find radius as a function of y for every disc.

fluid force on vertical side of tank the weight density of water is 62.4

To find the force I first need to find the volume of each disc and then multiply by the density, which the problem says is 62.4 lb/ft, so I only need to find the volume of each disc. To do this I am using the "disc-method" which subdivides a 3d solid into discs, in this case, a dome.

fluid force on vertical side of tank the weight density of water is 62.4

To find the Work I first needed to find the Force because Work = force*distance. How much work is required to fill the tank with water through a hole in the base when the water source is at the base? (The weight-density of water is 62.4 pounds per cubic foot.) A hemispherical tank of radius 2 feet is positioned so that its base is circular.













Fluid force on vertical side of tank the weight density of water is 62.4